(1/x+2)^2-4(1/x+2)-21=0

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Solution for (1/x+2)^2-4(1/x+2)-21=0 equation: 



(1/x+2)^2-4(1/x+2)-21=0



Domain of the equation: x+2)^2!=0

x∈R





Domain of the equation: x+2)!=0

x∈R



We multiply parentheses

(1/x+2)^2-4x-8-21=0

We multiply all the terms by the denominator


(1-4x*x+2)^2-8*x+2)^2-21*x+2)^2=0

We add all the numbers together, and all the variables

(-4x*x+3)^2-8*x+2)^2-21*x+2)^2=0

We add all the numbers together, and all the variables

-8x+(-4x*x+3)^2+2)^2-21*x+2)^2=0

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